WISE OWL EXERCISES
- Simple Queries (4)
- Setting criteria using WHERE (5)
- Calculations (7)
- Calculations using dates (4)
- Basic joins (8)
- More exotic joins (2)
- Aggregation and grouping (8)
- Views (5)
- Subqueries (5)
- Stored procedures (5)
- Variables (8)
- Parameters and return values (11)
- Testing conditions (1)
- Looping (3)
- Scalar functions (6)
- Transactions (5)
- Creating tables (5)
- Temporary tables and table variables (9)
- Table-valued functions (6)
- Derived tables and CTEs (13)
- Dynamic SQL (4)
- Pivots (2)
- Triggers (2)
- Archived (70)
SQL | Scalar functions exercise | Create a scalar function to determine type of each episode
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You can learn how to do this exercise if you attend the course listed below!
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First (if you haven't already done so) run the script shown above to generate the Doctor Who training database.
The aim of this exercise is to create a function called fnEpisodeDescription such that you can count how many episodes there are of each type:
-- count number of episodes of each type
dbo.fnEpisodeDescription(Title) AS 'Episode type',
COUNT(*) AS 'Number of episodes'
Here's what this should return:
It's reassuring to see that the number of first and second parts are the same!
To write this function use the CHARINDEX function to determine whether one string of text exists within another:
Your function should look for the word Part 1 (or failing that, Part 2) in the title passed in.
As a guide, CHARINDEX('owl','Wise Owl') would return 6, whereas CHARINDEX('fox','Wise Owl') would return 0.
When you've got your function and query working, save (optionally) the SQL as Part of a couple.sql, then close it down.